Skyshroud Sentinel
Creature — Elf
When this creature enters, you may search your library for up to three cards named Skyshroud Sentinel, reveal them, put them into your hand, then shuffle.
- CMC
- 3
- Mana cost
- Color identity
- G
- Rarity
- common
- Set
- Nemesis
- Price
- $0.14
- EDHREC rank
- #30993
Skyshroud Sentinel enters and immediately fetches a Forest from your library onto the battlefield, giving you a body and a land drop in one card. The cost is running a 1/1 for 1G with no other text — it lives and dies by whether your deck needs the redundancy of Wheel of Sun and Moon-adjacent consistency in its mana base.
Format Analysis
Where it lives, where it can’t
| Format | Verdict |
|---|---|
| commander | legal |
| legacy | legal |
| modern | not legal |
| pioneer | not legal |
| standard | not legal |
| vintage | legal |
| pauper | legal |
| oathbreaker | legal |
In Commander, Skyshroud Sentinel fills a narrow role in Forest-heavy decks that want every possible copy of a land-fetching effect — think 99-card consistency over raw power. Legacy and Vintage are legal but have no interest in a 1/1 that fetches a basic; faster, stronger options exist at every turn. Pauper is where Skyshroud Sentinel sees its most legitimate consideration, slotting into aggressive or midrange green shells that want to hit land drops reliably while building a board. Oathbreaker follows the same logic as Commander: niche, but functional in the right shell.
Key Combos
Combo lines featuring this card
Wheel of Sun and MoonAshnod's AltarEarthcraftSkyshroud Sentinel
Infinite death triggers; Infinite ETB; Infinite LTB; Infinite sacrifice triggers; Infinite storm count
View on Commander Spellbook ↗Price Context
Current price
$0.14 bulk tier
At $0.14, Skyshroud Sentinel is pure bulk — you're buying a playset for less than a pack. The price reflects the narrow demand; it won't rise unless a format shift suddenly makes redundant Forest-fetchers on a body desirable at scale.
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Sources
Updated . Data from Scryfall, EDHREC, and Commander Spellbook.